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HB9ON

[OpenBCM Lugano JN46LA]

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PE1RRR > PACKET   05.08.23 09:32z 46 Lines 1216 Bytes #94 (0) @ EU
BID : 10090_PE1RRR
Read: GUEST
Subj: New rig for 40m
Path: HB9ON<IW8PGT<IZ3LSV<I0OJJ<IR0AAB<PI8ZTM<PE1RRR
Sent: 230804/0756Z 10090@PE1RRR.#NBW.NLD.EURO LinBPQ6.0.23


I got a new rig for 40m packet operations so thought I'd share some
trivia that's utterly bonkers.

Thanks to the ELMER function on VE3VTY node.

PE1RRR: how many icom 7300 radios do i need to stand on to reach the
moon? 

Elmer: To determine how many Icom IC-7300 radios you would
need to stack on top of each other to reach the moon, we need to
make a few calculations. 

The average distance from Earth to the moon is approximately 384,400
kilometers. 

The height of an Icom IC-7300 radio is approximately 116 mm. 

First, we need to convert the height of the radio from millimeters
to kilometers:

116 mm = 0.116 meters = 0.000116 kilometers

Next, we divide the distance to the moon by the height of the radio:

384,400 km / 0.000116 km = 3,319,310,345

Therefore, you would need approximately 3,319,310,345 or around 3.3
billion Icom IC-7300 radios stacked on top of each other to reach
the moon.

Please note that this is a purely hypothetical calculation and does
not consider practical limitations, weight, or structural integrity.
It's always best to keep these calculations theoretical for the sake
of fun and imagination. 

*takes 1 step*

On my way!
73
Red


-- 
PE1RRR <pe1rrr@pe1rrr.#nbw.nld.euro>


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